LAST QUESTIONS, PLease helppp., pleaseeeee (BIOLOGY PACKET)?

4. A woman is homozygous for A-negative blood type. A man has AB-negative blood type. What is the probability that the couple's child will be type B-negative?Hint





A. 0%


B. 25%


C. 50%


D. 75%


E. 100%








5. Which pattern(s) of inheritance are consistent with the pedigree? Hint





1. Sex-linked


2. Complete dominance


3. Codominance











A. I only


B. II only


C. I and II only


D. II and III only


E. I, II, and III





6. What are the probable genotypes of the student's parents?Hint





A. Mother—Ww; Father—ww


B. Mother—ww; Father—ww


C. Mother—WW; Father—Ww


D. Mother—WW; Father—WW


E. Mother—Ww; Father—Ww





7. The student does not have a widow's peak hairline, but her sister does. What are the girls' probable genotypes?Hint





A. Student—Ww; her sister—ww


B. Student—WW; her sister—Ww


C. Student—ww; her sister—Ww


D. Student—ww; her sister—ww


E. Student—Ww; her sister—Ww

LAST QUESTIONS, PLease helppp., pleaseeeee (BIOLOGY PACKET)?
4.A. 0%. The homozygous woman is AA--; she will always give an "A" gene to her child. The father will give either A or B, so the child will be either AA (type A blood) or AB (type AB blood). Both will always give a "-" gene, so the child will always have - blood. A- or AB- are the only possibilities, so there is zero chance of B- blood.





5-7 We need to see the pedigree to answer these questions.





5. B


6. E


7. C





Explanation of these answers:





You can tell that the gene isn't X-linked because affected mothers always pass this to their sons when it is X-linked. You can see that this isn't true from the second family group.





You can tell that it isn't codominance because there is no in-between given. You need to have a situation where there is a mixing of genes (like red flowers and white flowers have pink flowered children), as opposed to either on or off like this.





This just leaves complete dominance.





In this case, you can tell that the first parents were:





Affected parents: Ww (have one affected gene, which dominates, so they have the affected phenotype)


Unaffected parents: ww (have no affected gene, so don't show the phenotype)





The affected children from this group will be Ww (one "W" gene from the affected "Ww" parent, and one "w" gene from the unaffected "ww" parent). This is the student's parents--both are affected, but both are carriers of the unaffected gene.





The student (unaffected) is "ww". Her sister is either WW or Ww (both are possible). However, the other possibility that matches your answers is "C". Also, Ww is more likely than WW (2/3 of the time, she would be Ww anyway).
Reply:4) A


5) C i think


6) ??


7.) C cus widow peak is dominant
Reply:4. A


5.C


6.E


7.C





(hint) somebody need to pay more attention to biology ****


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survey monkey